derive the equation of kinetic energy of a body of mass moving with velocity
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The relation connecting the initial velocity (u) and final velocity (v) of an object moving with a uniform acceleration a, and the displacement, S is
v2 - u2 = 2aS
This gives
S = ½a(v2 - u2)
We know F = ma. Thus using above equations, we can write the workdone by the force, F as
W = ma × ½a(v2 - u2)
or
W =m( v 2 - u 2 ) ½
If object is starting from its stationary position, that is, u = 0, then
W = ½mv2
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It is clear that the work done is equal to the change in the kinetic energy of an object.
If u = 0, the work done will be W = ½mv2
Thus, the kinetic energy possessed by an object of mass, m and moving with a uniform velocity, v is Ek= ½mv2
v2 - u2 = 2aS
This gives
S = ½a(v2 - u2)
We know F = ma. Thus using above equations, we can write the workdone by the force, F as
W = ma × ½a(v2 - u2)
or
W =m( v 2 - u 2 ) ½
If object is starting from its stationary position, that is, u = 0, then
W = ½mv2
<font size="1"> </font>
It is clear that the work done is equal to the change in the kinetic energy of an object.
If u = 0, the work done will be W = ½mv2
Thus, the kinetic energy possessed by an object of mass, m and moving with a uniform velocity, v is Ek= ½mv2
lumbi:
hi
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let a body with mass,m is moving with a velocity,u along a distance,s. a force,F acting on it changes its velocity,v.
we know that W=Fs--------------(1)
F=ma--------------(2)
2as=v^2-u^2
s=v^2-u^2/2a---------------(3)
from equations 1,2,3
W=ma×v^2-u^2/2a
W=1/2mv^2-u^2
if initial velocity is 0
then
W=1/2mv^2
if the answer helped you please mark me the BRAINLIEST
we know that W=Fs--------------(1)
F=ma--------------(2)
2as=v^2-u^2
s=v^2-u^2/2a---------------(3)
from equations 1,2,3
W=ma×v^2-u^2/2a
W=1/2mv^2-u^2
if initial velocity is 0
then
W=1/2mv^2
if the answer helped you please mark me the BRAINLIEST
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