derive the equation of motion by graphical method of class 9
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Answered by
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hope it's help you.
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Vishalkannaujiya:
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Answered by
32
Hey buddy here's your detailed derivation..
S={(OA+BC) ×OC}÷2
S={(u+v)×t}÷2
S={(u+v)/2}×{(v-u)/a}. [bcoz a= v-u/t]
S=(v^2-u^2)÷2a
or 2as= v^2-u^2..
S={(OA+BC) ×OC}÷2
S={(u+v)×t}÷2
S={(u+v)/2}×{(v-u)/a}. [bcoz a= v-u/t]
S=(v^2-u^2)÷2a
or 2as= v^2-u^2..
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but i can click only two pics...
I didn't get it
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mene answer edit kr diya h.. rest aap waha se dekh le..
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