Question

Derive The Equation Of Motion For A Particle Projected Vertically

Answer 1

Answer:

Dear Student,

Derivationw ould go like this:

Tower ht=h1

v=u+at

=>0=u-gt

=>t=u/g

max ht=ut-gt2/2

=>h=u2/2g

time to go up=u/g

time to come back=u/g

total time=2u/g

v2=u2+2gh1

=> velocity with which the body reaches the ground= v = √(u^2+2gh1)

max ht above the ground = h+h1

=u2/2g + h1.

Cheers!!

Regards,

Vikas (B. Tech. 4th year

Thapar University)

Answer 2

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