Question

derive the equation of motion, range and maximum height reached by the particle thrown at an oblique angle with respect to the horizontal direction ​

Answer 1

Explanation:

Horizontal range (R):

= ucos θ x Tf = u2sin2θg The horizontal range directly depends on the initial speed (u) and the sine of angle of projection (θ). It inversely depends on acceleration due to gravity 'g'. For a given initial speed u, the maximum possible range is reached when sin 2θ is maximum, sin 2θ = 1