derive the equation of motion range and maximum height reached by a particle thrown at an oblique angle with respect to the horizontal direction
Answers
Answered by
2
Explanation:
max. height final velocity is 0
in hz. direction velocity is ucostheta
acceleration due to gravity is -g
from equation of motion
v^2=u^2+2gh
0=u^2cos^2theta+2(-g)h
2gh=u^2cos^2theta
h=u^2cos^2theta/2g
Similar questions