Derive the equation of motion S = Ut + ½ at 2 using v-t graph
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Let us suppose that an object in uniform acceleration 'a' and it has covered the distance 's' within time 't'. from the graph do stand is covered by an object's during time't' it given by the area of quadrangle DOEB.
Explanation:
s= area of quadrangle DOEB
= area (rectangle DOEA) + area 9f triangle(DAB)
s= ( AE×OE) + (1/2×(Ab×Da) )
s= u×t+1/2×at×t
s=ut+1/2at^2
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