Question

derive the equation of motions for a body having constatnt acceleration​

Answer 1

Kinematical equations in one dimension:

It is given that body is moving with a constant acceleration.

1. a=v-u/t

: . v-u=at

: . v=u+at...................... (1)

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2. Distance covered in 't' seconds.

s=(average velocity) ×time

: . s=(v+u/2) ×t

: . s=(u+at) +u/2×t

: . s= (2u+at/2) ×t

: . s=(u+1/2at) t

: . s=ut+1/2at²................ (2)

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3. v=u+at

Squaring on both sides,

v²=u²+a²t²+2uat

: . v²=u²+a(at²+2ut)

: . v²=u²+2a(1/2at²+ut)

: . v²=u²+2a(ut+1/2at²)

: . v²=u²+2as........... (3)