Question

derive the equation of the trajection of a projectile​

Answer 1

Explanation:

When a body is thrown with velocity making some angle with horizontal,it follows parabolic trajectory called projectile.

At general time ,velocity of the particle will be vcosθ

i

^

+(vsinθ−gt)

j

^

v

x

=vcosθ

v

y

=(vsinθ−gt)

X=vcosθt

Y=vsinθt−

2

gt

2

Eliminating t,Y=

vcosθ

vsinθx

−

2v

2

cos

2

θ

g×x

2

Y=xtanθ−

2u

2

cos

2

θ

g×x

2

is called equation of trajectories