derive the equation of v2 _u2 =2as
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firstly you have to make a velocity time graph then u have to take the area of tapezium let this be the equation ist and then u have to take the first equation of motion v=u+at and solve it like v_u/a=t let this be equation 2 . substitute the value of 2 in 1 and do it like s=1/2(v+u) /ait will come as 2as =( v+ u)(v_u) then at last the formula is derived v2_u2=2as
hope this helps u
hope this helps u
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