Question

Derive the equation
s=ut +1/2 at^​

Answer 1

Explanation:

At t = 0, initial velocity = u = OA

At t = t, final velocity = v = OC

The distance S travelled in time t = area of the trapezium OABD

s = (1/2) x (OA + DB) × OD

s = (1/2) x (u + v) × t

Since v = u + at,

s = (1/2) x (u + u + at) × t

s = ut + (1/2) at2

Answer 2

Answer:

at ka 2 hoga

Explanation:

at^2 hogaya ga