Derive the equation: s = ut + 1/ 2 at2 by using graphical method.
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In this graph consider,
OABC as a trapzeium
wkt,
area of trap= 1/2(sum of paraell sides)×h
so, area of trap is the distance covered
so area of trap = s
now paraell sides are AO and BC and h is OC
SO,
S=1/2(AO +BC)×OC
OR, (according to garph)
s=1/2(v+u)×t
(by first equation of motion)
(v=u+at)
s=1/2{u+at+u}t
s=1/2{2u/t+at2}
S=Ut+1/2At2
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Answered by
8
Answer:
Your answer is
In this graph consider,
OABC as a trapzeium
wkt,
area of trap= 1/2(sum of paraell sides)×h
so, area of trap is the distance covered
so area of trap = s
now paraell sides are AO and BC and h is OC
SO,
S=1/2(AO +BC)×OC
OR, (according to garph)
s=1/2(v+u)×t
(by first equation of motion)
(v=u+at)
s=1/2{u+at+u}t
s=1/2{2u/t+at2}
S=Ut+1/2At2
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