Question

Derive the equation s=ut+1/2at^2 using speed time graph

Answer 1

u = initial speed
 t = time taken
 S = {distance in 1st sec} + {distance in 2nd sec } + {distance in 3rd sec) + ............... + {distance in t sec}
S = {u } + {u + a} + {u + 2a } + ................... + {u + (t - 1)a}
S = u * t + {a + 2a + .........+ (t - 1)a }
 S = ut + a( 1 + 2 + 3 ........+ (t-1))
 S = ut + a * t * (t -1) / 2
 https://youtu.be/WJN_F3PYp58

Answer 2

This is your answer:-

u = initial speed

t = time taken

S = {distance in 1st sec} + {distance in 2nd sec } + {distance in 3rd sec) + ............... + {distance in t sec}

S = {u } + {u + a} + {u + 2a } + ................... + {u + (t - 1)a}

S = u * t + {a + 2a + .........+ (t - 1)a }

S = ut + a( 1 + 2 + 3 ........+ (t-1))

S = ut + a * t * (t -1) / 2

I hope it will be helpfull to U

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