derive the equation S=ut+1/2at².where the symbols have their usual meanings.
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s = ut + 1/2 at^2
Derivation:-
We know that, s = v x t
=> s = [(u+v)/2]t
=> s = [(u+u+at)/2]t
=> s = [(2u+at)/2]t
=> s = [(u + (1/2)at)]t
=> s = ut + (1/2)at^2
Derivation:-
We know that, s = v x t
=> s = [(u+v)/2]t
=> s = [(u+u+at)/2]t
=> s = [(2u+at)/2]t
=> s = [(u + (1/2)at)]t
=> s = ut + (1/2)at^2
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