derive the equation s = ut+1at^2/2
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Answered by
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Explanation:
velocity = displacement/time
Vavg =s/t
s = Vavg.t
= (v+u/2)t
= (u+at +u/2)t
= (2u + at /2)t
= 2ut + at²/2
= ut +1/2at² -----> hence proved
Answered by
1
Solution:-
Now
=> For one dimensional motion with a = constant
We can write
Integrating both side we have
At t=0 , velocity is u and at t = t velocity is v hence
So
Further , we can write
At time t = 0 suppose s = 0 and at t = t , displacement is s then
Hence proved
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