Derive the equations of motion, both in integral an graphical method?
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By using calculus
1). Acceleration is given as rate of change of velocity
a=dtdv
Now on integrating both sides
a∫0tdt=∫uvdv
On solving the above we get
v=u+at
2). Rate of the displacement is equal to velocity
v=dtds
On integrating the above equation we get
∫0sds=v∫0tdt
On substituting the value ofv=u+at
We get
s=ut+21at2
3). Distance travelled is equal to average speed time time
s=2u+vt
By using the first equation and substituting the value oft=av−u
We get
v2=u2+2as
I hope it's help you
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Answer:
- First Equation of Motion: v = u + at. Second Equation of Motion: s = ut + 1/2(at2) Third Equation of Motion: v2 = u2 – 2as.
Explanation:
draw the graph
Attachments:
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