Question

Derive the expression for
3rd equations of motion in calculus method ​

Answer 1

Answer:Newton's 3rd law of motion: Every action in the universe have their equall and opposite reaction..

Newton's 3rd equation of motion consists of final velocity (v), initial velocity(u), displacement (s) and constant acceleration (a). The equation is as follows-

v²= u²+2as

Actually I don't know how to derive it. But here is some hints are provided.

You want it by integration.

(v² - u²) /2 indicates the integration of v dv limit u to v.

Here is the proof -

a= dv/dt……1

v=ds/dt……….2

from 1 & 2:

a ds/dt = v dv/ dt

implies a ds =v dv

after integration you will get 3rd equation. (pic of integration is shown above the matter).

Hope it will help...

Explanation:Follow me

Answer 2

Answer:

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