Question

Derive the expression for effective capacitance when n capacitors are connected in series

Answer 1

Answer:

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your answer is...

Explanation:

capacitors in series : when capacitance are connected in series, the charge remains constant but voltage varies, so

V = V1+V2+V3.

we know that C=Q/V implies V=Q/C

therefore ,

Q/C = Q/C1 + Q/C2 + Q/C3

1/C = 1/C1 + 1/C2 + 1/C3

is the resultant capacitance when capacitors are connected in series.

capacitors in parallel:

when capacitance are connected in parallel, then charge varies but voltage remains constant so,

Q = Q1 + Q2 + Q3

we know that C = Q/V implies Q = CV

therefore,

CV = C1V + C2V + C3V

implies

C = C1 + C2 +C3

is the resultant capacitance when capacitors are connected parallel.

hope my answer is useful to you..!!

Than you!

Answer 2

Explanation:

Vt = V1 +V2 V....n

Q/ep =. Q/C1 +Q/C2....... Qtotal/Cn

1/C1+ 1/C2......... 1/Cn.