Question

Derive the expression for horizontal range of a projectile.
explain step by step​

Answer 1

Answer:

The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from.

Explanation:

we know that time period of a projectile is

T=2(u)sinA/g

where u is the initial velocity with which the projectile is thrown.

for finding range we have to use only the horizontal component of velocity that is Ux (ucosA).

Now,

distance =speed xtime

R=(Ux)T

R=(ucosA)(2usinA)/g

R=2u²sinAcosA/g where 2sinAcosA= sin2A

R=U²sin2A/g

hope this helps .