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Derive the expression for Joule's heating effect of current..

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Answered by DIVINEREALM
78

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JOULE'S HEATING EFFECT

According to Joules law of heating, when a current I flows through a resistance R then :

Heat produced is :

(I) Directly proportional to the square of current for a given resistance

(II) Directly proportional to the resistance of given circuit.

(III) Directly proportional to the time for which the resistance flows through the resistor.

So eqⁿ is \bold{\huge{\red{H=I^2Rt}}}

\bold{\huge{\boxed{\pink{DERIVATION}}}}

let us consider a resistance R , in which I amount of current flows.

Work must be done by current to move continuously.

W=Qx V

BUT Q=IXt

W=IxVxt

but from ohms law: V=IR

\bold{\huge{\red{W=I^2Rt}}}

assuming the electrical energy consumed is converted into heat energy .

we write work done as Heat  produced.

so \bold{\underline{\huge{\red{H=I^2Rt}}}}

\bold{\huge{\boxed{\pink{APPLICATION}}}}

❶ In electrical heaters.

❷ In electrical iron

❸ In electrical fuse wire

❹ In electrical bulb

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Answered by DeviIQueen
8

Answer:

JOULE'S HEATING EFFECT

According to Joules law of heating, when a current I flows through a resistance R then :

Heat produced is :

(I) Directly proportional to the square of current for a given resistance

(II) Directly proportional to the resistance of given circuit.

(III) Directly proportional to the time for which the resistance flows through the resistor.

So eqⁿ is \bold{\huge{\red{H=I^2Rt}}}

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