Derive the expression for position time relation by graphical method.
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Heya,
Answer to your question is:-
Equation for distance –time relation
Distance covered by the object in the given time ‘t’ is given by the area of the trapezium ABDOE
Let in the given time, t the distance covered by the moving object = s
The area of trapezium, ABDOE
= Distance (s) = Area of △ABD+△ABD+Area of ADOE
⇒s=1/2×AB×AD+(OD×OE)
⇒s=1/2×AB×AD+(OD×OE)
⇒s=1/2×DC×AD+(u+t)
⇒s=1/2×DC×AD+(u+t)
[Since,AB=DC]
⇒s=1/2×at×t+ut
⇒s=1/2×at×t+ut
⇒s=1/2×at×t+ut
⇒s=1/2×at×t+ut
[∵ DC=at]
⇒s=1/2at2+ut
⇒s=1/2at2+ut
【⇒s=ut+1/2at²】
HOPE THIS HELPS YOU:-))
@Ashu
Answer to your question is:-
Equation for distance –time relation
Distance covered by the object in the given time ‘t’ is given by the area of the trapezium ABDOE
Let in the given time, t the distance covered by the moving object = s
The area of trapezium, ABDOE
= Distance (s) = Area of △ABD+△ABD+Area of ADOE
⇒s=1/2×AB×AD+(OD×OE)
⇒s=1/2×AB×AD+(OD×OE)
⇒s=1/2×DC×AD+(u+t)
⇒s=1/2×DC×AD+(u+t)
[Since,AB=DC]
⇒s=1/2×at×t+ut
⇒s=1/2×at×t+ut
⇒s=1/2×at×t+ut
⇒s=1/2×at×t+ut
[∵ DC=at]
⇒s=1/2at2+ut
⇒s=1/2at2+ut
【⇒s=ut+1/2at²】
HOPE THIS HELPS YOU:-))
@Ashu
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