Derive the expression for power dissipated across a resistor connected to a cell in terms of its resistance r
Answers
Answer:
As P=w/t
from above eq,,,,,P=IV
so as v=IR
put it in eq above
it become p=I(IR)
P=I²R
The circuit is made up of a variable power supply, a variable resistor R and, a light bulb all connected in series.
An ammeter, placed in series, allows the current, I, to be measured. A voltmeter connected in parallel with the resistor, R, allows the voltage across the resistor VR to be measured.
The light bulb acts like a resistor, RA, with resistance equal to 10Ω.
The curve shows the power dissipated in the the resistor. The unit of power is the Watt (W).
P = VR x I = R x I2
When the voltage is increased, the current, I, increases and the power dissipated by the resistor, R, increases.
When the value of the resistor is increased, I decreases and the power dissipated by the resistor, R, decreases.
The variable resistor, R, allows control