Question

derive the expression for rate constant for third order reaction with equal initial concentration.​

Answer 1

Answer:

If the reaction is third order, the rate constant should have units of L2 mol-2 s-1

Answer 2

Answer:

N is the total number of reactant molecules and [A]0 is the initial concentration of the reactant.

Explanation:

From the above question,

They have given :

The rate law for a third-order reaction is typically given as:

           Rate = k[A]$.^3$

Where [A] is the concentration of the reactant and k is the rate constant.

           [A]0 is the initial concentration  

           N is the total number of reactant molecules.

Substituting this into the rate law gives:

            Rate = k ([A]0/N)$.^3$

Rearranging this expression:

            k = Rate / ([A]0/N)$.^3$

            k = (Rate x $N^3$) / [A]$0^3$

Therefore, the expression for the rate constant for a third-order reaction with equal initial concentration is:

            k = (Rate x $N^3$) / [A]$0^3$

Here N is the total number of reactant molecules and [A]0 is the initial concentration of the reactant.

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