Question

derive the expression for relation between cp and cv​

Answer 1

The specific heat of gas at constant volume in terms of degree of freedom 'f' is given as: Cv = (f/2) R. So, we can also say that, Cp/Cv = (1 + 2/f), where f is degree of freedom.

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Answer 2

hey mate☺

✮solution✮

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Heat (q) at constant volume is given as,

Qv = Cv∆T = ∆U

Heat (q) at constant pressure is given as,

Qp = Cp∆T = ∆H

but,

H = U + PV

for 1 mole of gas, PV = RT

: H = U + RT

: ∆H = ∆U + ∆(RT)

or

∆H = ∆U + R∆T

∆H - ∆U = R∆T________(i)

Lets substitute values of ∆H and ∆U in eq.(i), we get:

Cp∆T - Cv∆T = R∆T

$\huge{\boxed{\simple\whute{\fcolorbox{}{}{Cp - Cv = R}}}}$

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