Derive the expression for tension and acceleration of a system consisting of two bodies attached to the ends of string that passes over a frictionless pulley,when both the bodies are moving veritcally
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Answered by
1
Answer:
Force balance equations for two weights can be written as:
T
1
=m
1
g−m
1
a---------(i)
and T
2
=m
2
a+m
2
g----------(ii)
(ii)-(i), we get:
T
1
−T
2
=(m
1
−m
2
)g−(m
1
+m
2
)a------------(iii)
As torque, τ=Iα, we have:
(T
1
−T
2
)R=(
2
1
MR
2
).
R
a
or, T
1
−T
2
=
2
Ma
Substituting this in equation (iii), we get:
2
Ma
=(m
1
−m
2
)g−(m
1
+m
2
)a
or, a=
m
1
+m
2
+(m/2)
(m
1
−m
2
)g
Answered by
0
Explanation:
Here, T1and T are different strings are used
Attachments:
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