Physics, asked by sy748916, 3 months ago

Derive the expression for the displacement of a transverse progressive

wave.​

Answers

Answered by hema352
12

Answer:

In case of transverse wave displacement is given as: y(x,t) where x=propagation of the wave along x-axis, and particles oscillates along y-axis. Therefore y(x,t)= A sin(kx – ωt + φ). This is the expression for displacement.

Answered by NamrataSachdeva
0

Answer:

y = A sin(kx - ωt) is the expression for the displacement of a transverse progressive.

Explanation:

The displacement of a transverse progressive wave can be derived using the wave equation, which describes how waves propagate through a medium. The wave equation for a transverse wave is:

∂²y/∂x² = (1/v²) * ∂²y/∂t²

where y is the displacement of the wave, x is the position along the wave, t is time, and v is the velocity of the wave.

Assuming that the wave is travelling in the x direction with a constant velocity, we can separate the variables and write:

y = A sin(kx - ωt)

where A is the amplitude of the wave, k is the wave number (2π/λ), λ is the wavelength of the wave, and ω is the angular frequency (2πf), where f is the frequency of the wave.

The displacement of the wave at any position x and time t can be found by substituting the values of k, ω, x, and t into the equation:

y = A sin(kx - ωt)

For example, if we want to find the displacement of the wave at a position x = 0.5m and time t = 0.2s, we can plug in the values:

y = A sin(k0.5 - ω0.2)

The value of k and ω depend on the properties of the medium through which the wave is travelling, such as its density and elasticity. The wavelength λ and frequency f are related to the velocity of the wave v through the equation:

v = λf

Therefore, the displacement of a transverse progressive wave can be described by the equation:

y = A sin(kx - ωt)

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