Derive the expression for the electric potential due to an electric dipole at a point on its axial line
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Hello mate here is your answer.
To calculate electric field created by a dipole on the axial line ( on the same line joining the two charges),
1)All the measurement of distances are to be taken from the centre(O).
2)the distance between O to +q and O to –q be ‘l’. So, total length between +q and –q will be ‘2l’.
3)Take a point ‘p’ on the axial line at the distance ‘r’ from the centre as shown in figure.
Hope it helps you.
To calculate electric field created by a dipole on the axial line ( on the same line joining the two charges),
1)All the measurement of distances are to be taken from the centre(O).
2)the distance between O to +q and O to –q be ‘l’. So, total length between +q and –q will be ‘2l’.
3)Take a point ‘p’ on the axial line at the distance ‘r’ from the centre as shown in figure.
Hope it helps you.
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