Derive the expression for the magnetic force on a staight wire carrying a current
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- We can derive an expression for the magnetic force on a current by taking a sum of the magnetic forces on individual charges. Noting that V=Al, where A is the cross-sectional area of the wire, then the force on the wire is F=(qvdBsinθ))(nAl).
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here's ur answer dude
Explanation:
We can derive an expression for the magnetic force on a current by taking a sum of the magnetic forces on individual charges. ... Noting that V=Al V = A l , where A is the cross-sectional area of the wire, then the force on the wire is F=(qvdBsinθ)(nAl) F = ( q v d B sin θ ) ( n A l ) .
hope it helps
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