Question

derive the expression for the moment of inertia of a thin uniform rod about an axis through its centre and perpendicular to its length also determine the radius of gyration about the same axis​

Answer 1

Explanation:

The moment of inertia of a rod of mass m about an axis perpendicular to it at one of its ends is given by I=ML

2

/3. Comparing this with the general equation for the moment of inertia, we get, I=MK

2

, K is the radius of gyration, we get K=L/

3