Question

Derive the expression for the time of flight and maximum height of projectile?​

Answer 1

Answer:

Consider a projectile fired with velocity V at an angle θ with horizontal.

From equations of motion we write y=ut+

2

1

at

2

Here, final displacement in y direction =0

⇒O=Vsinθ.t−

2

1

gt

2

⇒2Vsinθ=gt or

t=

g

2V

sinθ

→ Time of flight.