Question

derive the expression for the total energy of particular excusing simple hormonic motions
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Answer 1

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We will be using the formulae of simple harmonic motion x(t)=Acos(ωt+ϕ), Potential energy U=12kx2 , and Kinetic energy K.E=12mv2. Complete step by step answer: To find the total energy of the particle executing simple harmonic motion.

Answer 2

We will be using the formulae of simple harmonic motion x(t)=Acos(ωt+ϕ), Potential energy U=12kx2 , and Kinetic energy K.E=12mv2. Complete step by step answer: To find the total energy of the particle executing simple harmonic motion.