Question

derive the expression of 2nd equation of motion by v-t graph
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Answer 1

Answer:

Graphical derivation of 2nd equation of motion: Distance travelled s = area of trapezium ABDO ⇒ Area of rectangle ACDO + Area of ∆ABC s = OD × OA + 1 2 12 × BC × AC = t × u + 1 2 12 (v − u)t = ut + 1 2 12 (v − u)t. According to 1st eqn. of motion v = u + at v − u = at ∴ s = ut + 1 2 12at2Read more on Sarthaks.com - https://www.sarthaks.com/1029443/derive-second-equation-of-motion-with-the-use-of-v-t-graph