Question

derive the expression of equation of trajectory when a particle is projected from ground at an angle theta with speed u
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Answer 1

Explanation:

During flight, ucosθ=vcos2θ

v=cos2θucosθ

Normal acceleration of particle at point P is an=gcos2θ

an=rv2     

Here, r = radius of curvature

r=anv2

r=gu2cos2θsec32θ

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