Physics, asked by Paramjeet1247, 1 year ago

Derive the expression of for the conductivity of a wire in terms of number density and russian time

Answers

Answered by parakhcmd
4

first of all it not russian time it is relaxation time

next

we have a formula

I=neAV                        -------1

where

I=current

n=number density of electrons

A=area of cross section of wire

V=drift velocity

e=charge of electron

now,

V=eE/m(T)                   ------2

where

E=electric field intensity

T=relaxation time

m=mass of electron

put 2 in equation 1

we get I=(ne^2AE/m)T    ------3

we know that

E=V/lt                  ------4

where

V=potential

lt=length

put 4 in 3

I=(ne^2T/m)AV/lt

I/V=(ne^2T/m)A/lt

reciprocate,

V/I=(m/ne^2T)lt/A

we know that V/I=R

R=(m/ne^2T)lt/A      --------5

we also know that

R=(resistivity*lt)/A     ------6

hence compare 5 and 6

we get

resistivity=m/ne^2T

we know that conductivity=1/resistivity

hence the required expression is

conductivity=(ne^2T)/m

:)

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