Physics, asked by abhisheksingh258, 30 days ago

derive the expression of gausses theorem and if the radius of Gaussian surface enclosing a charge is halved, how does the electric flux through the Gaussian surface change?​

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Answered by RROBROY
0

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Answered by NITESH761
0

Answer:

. Total charge enclosed by the Gaussian surface remains same even when radius is halved. Therefore, total electric flux remains constant as per Gauss' theorem. There will not be any change in electric flux through the Gaussian surface.

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