derive the expressions for electric field at any point due to charged spherical shell using gauss theorem
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Answered by
1
Explanation:
Let, R be the radius of the shell and Q be the charge uniformly distributed on the surface.
i) For a point outside the shell :
By Gauss's law, E.4πr
2=
ϵ
0
Q
en
here r be the distance from centre of shell (r>R) and charge enclosed by surface Q
eq
=Q
So, E
out
=E=
4πϵ
0
r
2
Q
ii) For a point inside the shell :
By Gauss's law, E.4πr
2
=
ϵ
0
Q
en
here r be the distance from centre of shell (r<R) and charge inside the shell, Q
eq
=0
So, E
in
=E=0
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1
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