Derive the expressions for self and mutual inductances?
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Consider a current(I) is passed through the inductor (L).
A: Cross-sectional area
N : Number of turns
L : Length
Magnetic field generated at inside the solenoid is ,
B=
L
μ
o
NI
So, the flux through the coil is a obtained:
ϕ
B
=N(
B
.
A
) (
B
and
A
are along same direction)
ϕ
B
=
L
μ
o
N
2
IA
...(1)
Now, flux (ϕ
B
) is related to inductance (L) as
ϕ
B
=LI
⇒L=
I
ϕ
B
From (1) we get,
⇒L=
L
μ
0
N
2
A
Answered by
8
Answer:
Self inductance is the characteristic of the coil itself. Mutual inductance is the characteristic of a pair of coils. The induced current opposes the decay of current in the coil when the main current in the coil decreases
Explanation:
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