Question

derive the factor 0.014 for nitrogen for 1 ml 1N H2SO4​

Answer 1

Answer:

Define electronic configuration

Answer 2

Derivation of factor 0.014 for nitrogen for 1 ml 1N H2SO4​ :

$\text { Molar Mass of } \mathrm{H} 2 \mathrm{SO} 4=36.04 \text { A.M.U }\\\text { For make a } 1 \mathrm{~L} \text { solution of } 1 \mathrm{M} \mathrm{H} 2 \mathrm{SO} 4\\(36.04) X(x)=1 X(1)$

$x=1 X(1) /(36.04)\\\mathrm{x}=0.0277 \mathrm{gm} / \mathrm{ml} \text { of water }\\\mathrm{x}=27.7 \mathrm{~mL} \text { of } 36 \mathrm{M} \mathrm{H} 2 \mathrm{SO} 4 \text { per liter }$

$\text { Hence for } 1 \mathrm{~N} \text { H2SO4 dissolve } 27.7 \mathrm{ml} \text { of it to } 1000 \mathrm{ml} \text { of solvent(Water) }\\\text { that means for } 0.1 \mathrm{~N} \text { H2SO4 } 2.77 \mathrm{ml} \text { of it to } 1000 \mathrm{~mL} \text { of solvent. }$