Question

Derive the first equation of motion by graphical and calculus method

Answer 1

Answer:

sorry buddy my hand writing is not good

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\green{ANSWER:}$

✿ Deriving the first equation of motion [Velocity-time relation], graphically:-

v= u+at

Here,

OA= u= initial velocity=DC

OE= v= final velocity=BC

OC= t=time taken

Let the velocity of the body changes at a uniform rate. So, acceleration of the body= a(say)

From the graph,

BC= BD+DC

→BD=BC-DC

→BD= v-u [Consider it as the equation no. 1]

Now, acceleration from the graph can be calculated by the slope of the v-t graph.

and hence,

a= BC-DC/OC

→a= BD/t

→a= v-u/t [From equation 1]

→at= v-u (Reorder the sides)

→ v-u= at

→v= u+at [THE FIRST EQUATION OF MOTION]

⏩ Kindly, refer the second attachment for the CALCULAS METHOD!!!

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Hope it helps..:-)

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Be Brainly..✌✌✌

♠WALKER♣