Question

derive the following equation of motion by the geographical method v square equal to u square + 2as

Answer 1

this is the answer of your questions

Answer 2

distance travelled by trapezium = AOCB
area of trapezium = 1/2(sum of parallel sides)×h
= 1/2 ( OA + CB )× OC
= 1/2 ( u-v )× t
here,
t = v - u / a from equation ----------(1)
now,
s = 1/2 ( u-v ) × ( v-u )/ a
s = ( u + v ) ( v - u )/2a
s = v2 - u2 /2a
2as = v2 - u2
2as + u2 = v2
So,
$v {}^{2} =u {}^{2} + 2as$
I hope this will help you.
please mark it as brainliest.