Question

derive the following equations of motion of an object moving with constant acceleration by using velocity time graph V=u+at s=ut+1÷2at^2 v^2=u^2+2as​

Answer 1

Explanation:Suppose a body has initial velocity ‘u’ (i.e., velocity at time t = 0 sec.) at point ‘A’ and this velocity changes to ‘v’ at point ‘B’ in ‘t’ secs. i.e., final velocity will be ‘v’.