derive the formula and SI unit of electric power
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Answered by
2
Power is the amount of work done (or energy consumed) per unit time.
Let , Work done = W joules
Time taken = T seconds
![power = \frac{work \: done}{time \: taken} power = \frac{work \: done}{time \: taken}](https://tex.z-dn.net/?f=power+%3D++%5Cfrac%7Bwork+%5C%3A+done%7D%7Btime+%5C%3A+taken%7D+)
![\: \: \: \: \: = \frac{w}{t} joules \: per \: second \: \: \: \: \: = \frac{w}{t} joules \: per \: second](https://tex.z-dn.net/?f=+%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%3D++%5Cfrac%7Bw%7D%7Bt%7D+joules+%5C%3A+per+%5C%3A+second)
![power = \frac{w}{t \:} \: watt power = \frac{w}{t \:} \: watt](https://tex.z-dn.net/?f=power+%3D++%5Cfrac%7Bw%7D%7Bt+%5C%3A%7D++%5C%3A+watt)
Hence, Power = Work done / Time taken
The SI unit of power is joules per second or 'Watt'.
Let , Work done = W joules
Time taken = T seconds
Hence, Power = Work done / Time taken
The SI unit of power is joules per second or 'Watt'.
Answered by
61
Answer:
Explanation:
When a current I flows through a conductor under a potential difference of V for time t, the electric work done is given by,
Electric work done, W = VIt
Electric Power, P = VIt/t = VI
So, When a current of I amperes flows through a conductor under a potential difference of V volt, then
Electric power, P = V volt × I ampere = VI volt-ampere
P = VI watt = VI watt
P = VI W
Where V is the potential difference across the conductor in volts,
I is the current in the amperes flowing through the conductor.
So, if voltage and current are known, powers of an electrical appliance can be calculated.
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