derive the formula connecting the refractive index of a prism and angle of mean deviation.if the angle of prism is A.
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Answer:
In the given diagram,
OP is the incidence ray, which is making the angle i
1
with normal, and QR is the angle of emergence, which is represented by i
2
. A is the prism angle and μ is the refractive index of the prism.
Now, We know that,
A=Prism angle, δ=Angle of deviation, i
1
=Angle of incidence, i
2
=Angle of emergent.
In the case of minimum deviation,∠r
1
=∠r
2
=∠r
A=∠r
1
+∠r
2
SO, A=∠r+∠r=∠2r
∠r=
2
A
Now, again
A+δ=i
1
+i
2
(∵ In the case of minimum deviation
i
1
=i
2
=i and δ=δ
m
)
So, A+δ
m
=i+i=2i
Now, i=
2
A+δ
m
Now, from snell's rule,
μ=
sin r
sin i
μ=
sin
2
A
sin
2
A+δ
m
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