Question

Derive the formula cos2x=1-tansquarex/1+tan squarex
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Answer 1

Step-by-step explanation:

We have,

cos2x=cos^2x-sin^2x

=cos^2x-sin^2x/1

=cos^2x-sin^2x/cos^2x+sin^2x

=cos^2x{1-sin^2x/cos^2x}/cos^2x{1+sin^2x/. cos^2x}

therefore,

cos2x=1-tan^2x/1+tan^2x

Answer 2

Answer:

formula

Step-by-step explanation:

1-cos(2x)= (2x)^2/2!-(