derive the formula F = MA , WHERE F = FORCE , M = MASS , A = AECCELRATION
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Explanation:
Derivation :-
Let m be the mass of the body.
And its initial velocity is u.
Initial momentum, P₁ = mu .... (i)
After applying a constant force, F on this body
Accelerated to a velocity, v to time t
Then,
Mass of the body = m
Final velocity, = v
Final Momentum, P₂ = mv .... (ii)
Change in momentum = Final Momentum - Initial Momentum
Change in momentum = P₂ - P₁ .... (iii)
Now, According to 2nd law of motion,
F ∝ Change in momentum/Time taken
F ∝ P₂ - P₁/t [From Eq (iii)
F ∝ mv - mu/t [From Eq (i) and (ii)}
F ∝ m(v - u)t
F ∝ m(v - u/t) [From a = v - u/t]
F ∝ ma
F ∝ Ka [Where k is constant]
The value of K in SI unit is 1.
F = ma
Hence, Derived.
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