derive the formula for current in a looped conductor inserted in an old man's anus at 72 degrees to the vertical at 2:30 p.m. IST
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lol lol 1/ 2 -hosh
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Answer:
µ/4π I/r 2π
Explanation:
I am just going to assume that the you require the magnetic field at the center of the current carrying loop. This is because a point on the axis of the loop lies outside the old man's anus which gives rise to many mathematical complications. Hence i have given the equation for a point on the center of the loop.
Equation : µ/4π I/r 2π
However, please keep in mind that µ is the permeability of the space surrounding the coil, i.e. permeability of the old mans anus.
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