derive the formula for elastic potential energy for a stretched wire?
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Elastic potential energy is the potential energy stored by stretching or compressing an elastic object by an external force such as the stretching of a spring. It is equal to the work done to stretch the spring which depends on the spring constant k and the distance stretched.
According to Hooke’s law, the force applied to stretch the spring is directly proportional to the amount of stretch.
In other words,
Force required to stretch the spring is directly proportional to its displacement. It is given as
F = -kx
Wherein,
k = spring constant
x = displacement
The Elastic Potential Energy Formula of the spring stretched is given as
P.E = 1/2kx²
Where,
P.E = elastic potential energy and it’s expressed in Joule.
According to Hooke’s law, the force applied to stretch the spring is directly proportional to the amount of stretch.
In other words,
Force required to stretch the spring is directly proportional to its displacement. It is given as
F = -kx
Wherein,
k = spring constant
x = displacement
The Elastic Potential Energy Formula of the spring stretched is given as
P.E = 1/2kx²
Where,
P.E = elastic potential energy and it’s expressed in Joule.
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Expression for Gravitational Potential Energy at Height (h) – Derive ΔU = mgh. When, h<<R, then, R + h = R and g = GM/R2.
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