Derive the formula for heat current(H) flowing in a bar with its two ends maintained at temperatures Tc and Td
with Tc>Td
please provide full answer asap.. tia!
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∆Q/∆t ~ A(area of cross section).......(1)
∆Q/∆t ~ 1/L(length of conducting bar)...(2)
∆Q/∆t ~ Tc-Td (temperature difference)...(3)
from (1) (2) (3)
∆Q/∆t ~ A(Tc-Td)/L
∆Q/∆t = kA(Tc-Td)/L
where k= coefficient of thermal conductivity=constant
and ∆Q/∆t=rate of flow of heat or heat current
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∆Q/∆t ~ 1/L(length of conducting bar)...(2)
∆Q/∆t ~ Tc-Td (temperature difference)...(3)
from (1) (2) (3)
∆Q/∆t ~ A(Tc-Td)/L
∆Q/∆t = kA(Tc-Td)/L
where k= coefficient of thermal conductivity=constant
and ∆Q/∆t=rate of flow of heat or heat current
___HOPE IT HELPS ___
___PLEASE MARK IT AS BRAINLIEST__
Charu1702:
thanks
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