Derive the formula for kinetic energy of a particle having mass m and velocity v using diamensional analysis
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Answer:
KE = 1/2mv²
Explanation:
Let a particle of mass m be moving with velocity v. Suppose it's kinetic energy ia given by -
KE = k.m^x.v^y
In dimensional form,
[KE] = [m]^x.[v]^y
[L2M1T-2] = [M1]^x.[L1T-1]^y
[L2M1T-2] = [L^y.M^x.T^-y]
Comparing indexes,
y = 2
y = 2x = 1
Putting this in our previous equation -
KE = k.m^1.v^2
Value of k can be experimentally determined as 1/2,
KE = 1/2 mv²
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