Derive the formula for kinetic energy of
a particle having mass m and velocity v
using dimensional analysis
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We need to derive the formula for kinetic energy of a particle using dimensional analysis.
Solution :
Let m is the mass and v is the velocity of the object.
Let kinetic energy of the particle is km^xv^ykm
x
v
y
The dimensional formula of mass, [m]=[M]
The dimensional formula of velocity, [v]=[LT⁻¹]
Dimension of kinetic energy =[M][L^2T^{-2}][M][L
2
T
−2
]
Substitute both values of kinetic energy equal then we get
km^xv^y=[M][L^2T^{-1}]=[M^1][(LT^{-1})^2]km
x
v
y
=[M][L
2
T
−1
]=[M
1
][(LT
−1
)
2
]
Comparing both sides we get :
x=1 and y=2
So, the formula becomes :
E=kmv^2E=kmv
2
Let k = 1/2
So,
Kinetic energy, E=\dfrac{1}{2}mv^2E=
2
1
mv
2
Hence, this is the required solution.
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