Question

Derive the formula for wavelength in terms of accelerating potential V from de Broglie hypothesis

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Answer 1

Explanation:

When the charge particle is accelerated by a potential V, the kinetic energy is equal to electrostatic potential energy.

Thus,

2

1

mv

2

=qV or v=

2qV/m

Hence, the de Broglie wavelength, λ=

p

h

=

mv

h

=

2mqV